Happy Birthday Stoney Mike

dd

A big Happy Birthday to ya, Mike. Hope you have a great one and get lots of neat toys!<br />
<br />

jeweler jim

[color="#0000FF"][size="4"]May the bluebird of happiness grant you all your birthday wishes!<br />
<br />
[color="#099000"]Hope to make at least one of your shoots next month. [/size] [/color][/color]

Wrangler Rich

Happy Birthday, Mike!!!!<br />
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<img src='http://www.goodguysposse.org/forums/public/style_emoticons/<#EMO_DIR#>/hbinsc_e0.gif' class='bbc_emoticon' alt=':hbinsc_e0:' /> <br />
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<br />
WR<br />
<img src='http://www.goodguysposse.org/forums/public/style_emoticons/<#EMO_DIR#>/drinks.gif' class='bbc_emoticon' alt=':drinks:' />

StoneyMike

Thanks all for the Birthday Wishes. Spent the day at School and the night on homework. If anyone would care to share their expertise on Automated Cell design and Servo and Process controls I'd be VERY glad to hear it!!!

Snidely Whiplash

Well Mike, as we all know:<br />
<br />
<br />
if we let in ΔABC, angle C = 90. As usual, AB = c, AC = b, BC = a. Define points D and E on AB so that AD = AE = b.<br />
By construction, C lies on the circle with center A and radius b. Angle DCE subtends its diameter and thus is right: DCE = 90. It follows that BCD = ACE. Since ΔACE is isosceles, CEA = ACE.<br />
Triangles DBC and EBC share DBC. In addition, BCD = BEC. Therefore, triangles DBC and EBC are similar. We have BC/BE = BD/BC, or<br />
a / (c + b) = (c - b) / a.<br />
<br />
a = c - b,<br />
a + b = c. <br />
H(t) = ho - g t2 / 2 - vo t = ho - 32.2 t2 / 2 - vo t<br />
h = λ*/c^3 = 6.626068791897^-34<br />
<br />
Well, I'm sure you can take it from there. No need to thank me, anytime I can be of assistance, just let me know.<br />
<br />
Snidely

shamrock

Stoney Mike,<br />
Hope you had a great birthday and have many more.<br />
Regards,<br />
Pat "Shamrock" Gannon